Zig build : How to handle an unknown amount of files in a folder

[vulpesx]

Use b.build_root.handle to get a std.fs.Dir to the root of your project, open the directory of your resources via this will let you use the iterate() function to get a directory iterator.
b.addSystemCommand is your friend

@LucasSantos91

In your build.zig, iterate over your resources folder and call addOutputFileArg for each file to get a lazy path

use addInputFileArg too, otherwise zig won’t rebuild when the inputs change.

note both of those functions are on the step returned
By b.addSystemCommand

use b.addOptions() to get a *Options, this lets you declaratively make a module, much nicer and more useful than a WriteFile
works like this options.addOption(T, "option_name", value)
then add it to your root module with addOptions("import_name", options)
and you will be able to @import("import_name").option_name to your heart’s content :3