Is there a way to get the function name from pointer

Brainstorming
3

You can in a roundabout way. When you use a comptime function to define a struct type, the arguments given will end up in the type name:

const std = @import("std");

fn Useless(comptime arg: anytype) type {
    return struct {
        const stuff = arg;
    };
}

pub fn main() void {
    std.debug.print("{s}\n", .{@typeName(Useless(1234))});
    std.debug.print("{s}\n", .{@typeName(Useless(.{ .pierogi = 12 }))});
}

fname.Useless(1234)
fname.Useless(.{ .pierogi = 12 })

If you pass a function as an argument, the function name shows up:

pub fn main() void {
    const funs = comptime [_]FnType{
        foo1,
        foo2,
        foo3,
    };
    inline for (funs) |fun| {
        std.debug.print("{s}\n", .{@typeName(Useless(fun))});
    }
}

fname.Useless((function 'foo1'))
fname.Useless((function 'foo2'))
fname.Useless((function 'foo3'))

Now it’s just a matter of plucking it out.

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