How to return a C string from []u8

[Sze]

Hi @jailop, welcome to ziggit!

I edited your post, I think you meant []u8?

I think you are looking for std.mem.Allocator.dupeZ to convert []u8 to [:0]u8 and then you can use .ptr on that to pass it to C.

const c_str = try allocator.dupeZ(str);
defer allocator.free(c_str);
c_function(c_str.ptr);

Also take a look at this, for more details:

Convert []const u8 to [*:0]const u8

Hello @jjuel, welcome to the forum. Types: [*:0]const u8 is a sentinel terminated pointer, a pointer to 0 terminated string of u8. []const u8 is a slice, a pointer and a length. [:0]const u8 is a 0 terminated sentinel slice, a pointer to 0 terminated string and a length. Convertions: To convert from a zero terminated pointer to a slice use: std.mem.span . To convert from a 0 terminated sentinel slice to a zero terminated pointer call .ptr // "Hello" is a zero terminated array of u8 const …